# bitxor

bitwise XOR

## Calling Sequence

                z = bitxor(x, y)

## Parameters

x :

  a `m`-by-`n` matrix of doubles or a `m1`-by-`m2`-by-...-by-`mm` hypermatrix of doubles or a `m`-by-`n` matrix of unsigned integers (`uint8`, `uint16` or `uint32`). Must contain positive integer values.

y :

  a `m`-by-`n` matrix of doubles or a `m1`-by-`m2`-by-...-by-`mm` hypermatrix of doubles or a `m`-by-`n` matrix of unsigned integers (`uint8`, `uint16` or `uint32`). Must contain positive integer values.

z :

  a `m`-by-`n` matrix of doubles or a `m1`-by-`m2`-by-...-by-`mm` hypermatrix of doubles or a `m`-by-`n` matrix of unsigned integers.

## Description

Given `x` and `y` two positive integers, this function returns the decimal number `z` whose the binary form is the XOR of the binary representations of `x` and `y`.

## Examples

    // Compute the bitwise XOR of two matrices of doubles.
    x = [0 1 0 1];
    y = [0 0 1 1];
    z = bitxor(x, y)
    expected = [0 1 1 1];

    // Compute the bitwise XOR of two matrices of integers.
    x = uint8([0 1 0 1]);
    y = uint8([0 0 1 1]);
    z = bitxor(x, y)

    // The types of x and y cannot be mixed (error).
    x = [0 1 0 1];
    y = uint8([0 0 1 1]);
    // z = bitxor(x, y)

    //  13 is (01101)_2
    //  27 is (11011)_2
    // XOR is (10110)_2 which is 22.
    bitxor(uint8(13), uint8(27))
    bitxor(13, 27)